Impedance and matching
Understand resistance, reactance and reference planes using a calculable quarter-wave transformer.
- Interpret complex impedance.
- Recognise a matching model’s limits.
More than one number in ohms
ImpedanceImpedance is complex opposition to alternating current: it includes resistance and a frequency-dependent reactance. Antenna input impedance is therefore more than a DC resistance reading.Example & full explanation → is written Z = R + jX. R is resistance and X reactance. In the usual convention, positive X is inductive and negative X capacitive. Two loads with the same impedance magnitude can therefore behave differently on a line.
Resonance means X = 0 at the reference plane being considered. A resonant 100 Ω load is still not matched to a 50 Ω line. Conversely, a matching network can present a suitable impedance at the transmitter even when the antenna feed point itself has reactance.
↑ Back to contentsA narrowband transformer
An ideal lossless quarter-wave line transforms a resistive load according to Zin = Zt²/Rload. To join 50 and 100 Ω it therefore needs Zt = √(50·100) ≈ 70.71 Ω. Physical length then depends on frequency and velocity factor. Both characteristic impedance and length are part of the solution.
The quarter-wave condition applies at the design frequency and corresponding recurring electrical lengths. Changing frequency changes the transformation. The calculator assumes purely resistive terminations; entering the magnitude of a complex antenna load is not a valid substitute.
↑ Back to contentsAlways identify the reference plane
A measurement at the radio includes the feed line’s effect. A measurement directly at the antenna connector observes a different plane. Calibrate suitable equipment at the intended plane or account for the line with an appropriate model. Otherwise the same antenna may appear to have different impedances merely because the measurement location changed.
↑ Back to contentsFrom reading to experimenting
Quarter-wave impedance transformer
An ideal match between 50 and 100 Ω requires 70.71 Ω. Length then depends on frequency and VF.
Open example with starting values →Side A impedance: 50 Ω · Side B impedance: 100 Ω · Frequency: 14.2 MHz · Velocity / shortening factor: 0.66Then change exactly one value. Compare the result and use the formula to explain why it changes. The model limits below the calculator also apply here.
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An antenna is resonant at 100 + j0 Ω. Is it therefore matched to 50 Ω?
Show answer & explanation
No. Reactance is zero, but resistance is twice the reference. The ideal SWR is 2:1.