Estimating battery runtime realistically
Combine transmit duty cycle, receive current and usable capacity in a transparent runtime model.
- Calculate time-averaged current.
- Distinguish the model from real battery limits.
Operating pattern matters
A radio usually draws different currents in transmit and receive. A simple model splits operating time between those two states. With 20% transmit duty cycle, 5 A transmit current and 0.5 A receive current, Iavg = 0.2·5 + 0.8·0.5 = 1.4 A.
Use suitable measurements or specifications for the actual radio and operating point. With a varying signal envelope, average current can differ from peak current. Extra loads such as a HotspotA digital-radio hotspot connects a local radio access point to a digital network. Its modem, software and network configuration determine supported modes and features.Example & full explanation →, lighting or a converter also belong in the budget; the two-state calculator includes them only through appropriately adjusted inputs.
↑ Back to contentsUsable capacity, not just the label
A nominal 10 Ah battery with an assumed 80% usable capacity provides 8 Ah in the model. At 1.4 A average current, this gives about 5.71 hours. The 80% value is a planning assumption, not a general recommendation for every cell chemistry or battery type.
Temperature, ageing, discharge current, cutoff voltage and protection circuitry change available capacity. Current dependence is especially relevant for some battery types. A simple Ah/current calculation does not automatically model these effects. Measured runtime under comparable conditions is therefore more useful than extra decimal places.
↑ Back to contentsPlan an explicit reserve
Calculate several scenarios: normal operation, more transmitting and reduced usable capacity. Record the assumptions. If voltage during transmit peaks falls below the radio’s limit, it may shut down before the calculated Ah is used. Check wiring loss and loaded voltage as well as capacity.
↑ Back to contentsFrom reading to experimenting
Battery runtime
10 Ah, 80% usable, 0.5 A RX, 5 A TX and 20% transmit duty yield 1.4 A average and about 5.71 hours.
Open example with starting values →Nominal capacity: 10 Ah · Usable fraction: 80 % · Receive current: 0.5 A · Transmit current: 5 A · Transmit duty cycle: 20 % · Nominal voltage: 12.8 VThen change exactly one value. Compare the result and use the formula to explain why it changes. The model limits below the calculator also apply here.
Got the idea?
Why can a longer supply cable shorten usable operating time even with the same battery?
Show answer & explanation
Higher voltage drop can bring the radio to its undervoltage limit earlier during transmit peaks, and the wire also dissipates power.