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Inductors, capacitors and resonance

Calculate reactance and understand why an ideal resonance alone does not describe a real filter.

HB3YAQ · Ajdin HadzicLearning to take awayhttps://hb3yaq.ch/en/knowledge/lc-circuits
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WHAT YOU WILL LEARN
  • Distinguish inductive and capacitive behaviour.
  • Calculate LC resonance with correct units.
01

Frequency-dependent opposition

An ideal inductor has reactance XL = 2πfL, increasing with frequency. An ideal capacitor has XC = −1/(2πfC), whose magnitude decreases as frequency rises. The sign indicates the phase relationship; it does not mean a capacitor has negative resistive loss.

The formulas expect hertz, henries and farads. One microhenry is 10⁻⁶ H and one picofarad is 10⁻¹² F. The calculators handle these conversions. When calculating manually, confused prefixes are a common cause of results that are wrong by many orders of magnitude.

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02

When reactances cancel

At f₀ = 1/(2π√LC), the two ideal reactances have equal magnitude. In series they cancel. For 1 µH and 100 pF, this occurs at about 15.915 MHz. Ideal series ImpedanceImpedance is complex opposition to alternating current: it includes resistance and a frequency-dependent reactance. Antenna input impedance is therefore more than a DC resistance reading.Example & full explanation → becomes zero there; a real circuit retains its loss resistance.

In an ideal parallel circuit, the reactive parts of admittance cancel instead, making impedance very large in the lossless model. Series and parallel circuits must therefore not be treated as identical despite sharing the ideal resonance formula. Loading and losses determine what an installed resonator actually does.

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03

RF components are not ideal

An inductor also has capacitance and resistance; a capacitor also has parasitic inductance. Above self-resonance, expected behaviour can reverse. Check the data sheet, tolerance and suitable frequency range. Quality factor and connected loads determine BandwidthBandwidth is the width of a frequency range. A receiver filter limits the analysed range; the signal’s occupied bandwidth is a separate quantity.Example & full explanation →; the simple LC formula does not.

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From reading to experimenting

LC resonance

1 µH and 100 pF give approximately 15.915 MHz and a characteristic impedance of 100 Ω.

Open example with starting values →Inductance: 1 µH · Capacitance: 100 pF

Inductive & capacitive reactance

As frequency rises, XL increases and the magnitude of XC decreases. At LC resonance they cancel in series.

Open example with starting values →Frequency: 14.2 MHz · Inductance: 1 µH · Capacitance: 100 pF

Then change exactly one value. Compare the result and use the formula to explain why it changes. The model limits below the calculator also apply here.

TRY IT YOURSELF

Got the idea?

You quadruple C while keeping inductance fixed. How does ideal resonant frequency change?

Show answer & explanation

It halves because f₀ is inversely proportional to √C.